4j+2q+5=5q+2(j^2)

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Solution for 4j+2q+5=5q+2(j^2) equation: 


Simplifying
4j + 2q + 5 = 5q + 2(j2)

Reorder the terms:
5 + 4j + 2q = 5q + 2(j2)

Reorder the terms:
5 + 4j + 2q = 2j2 + 5q

Solving
5 + 4j + 2q = 2j2 + 5q

Solving for variable 'j'.

Reorder the terms:
5 + 4j + -2j2 + 2q + -5q = 2j2 + 5q + -2j2 + -5q

Combine like terms: 2q + -5q = -3q
5 + 4j + -2j2 + -3q = 2j2 + 5q + -2j2 + -5q

Reorder the terms:
5 + 4j + -2j2 + -3q = 2j2 + -2j2 + 5q + -5q

Combine like terms: 2j2 + -2j2 = 0
5 + 4j + -2j2 + -3q = 0 + 5q + -5q
5 + 4j + -2j2 + -3q = 5q + -5q

Combine like terms: 5q + -5q = 0
5 + 4j + -2j2 + -3q = 0

The solution to this equation could not be determined.

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